CUET · CHEMISTRY · PYQ PAPER 2023
0.04 F of charge will liberate how much of oxygen gas (at STP) from acidified water?
- A 448 ml
- B 672 ml
- C 224 ml
- D 112 ml
Answer & Solution
Correct Answer
(C) 224 ml
Step-by-step Solution
Detailed explanation
\(4 \, F \rightarrow 1 \, mol \, O_2\) \(mol \, O_2 = \frac{0.04 \, F}{4 \, F/mol} = 0.01 \, mol\) \(V_{O_2} = 0.01 \, mol \times 22.4 \, L/mol = 0.224 \, L = 224 \, mL\)
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