In species-area relationships equation - log S = log C + Z log A
'Z' denotes the -

Observe the figures and answer the question.

Match List I with List II.

LIST I	LIST II
A. Globular embryo	I. W
B. Mature embryo	II. Y
C. Zygote	III. Z
D. Heart-shaped embryo	IV. X

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Aphids and mosquitoes can be controlled by, respectively:

Match List - I with List - II.

List I	List ll
(A) Haemophilia	(I) Increase in a whole set of chromosomes in an organism
(B) Turner's Syndrome	(II) Autosome linked recessive trait
(C) Polyploidy	(III) Absence of one of the 'X' chromosome
(D) Sickle cell anaemia	(IV) Sex linked recessive disease

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Match List-l with List-II

List-l (Genetic disorder)	List-II (Characteristics)
(A) Haemophilia	(I) Mutation in HBB gene
(B) Thalassemia	(II) Sex-linked recessive disease
(C) Phenylketonuria	(III) Aneuploidy
(D) Klinefelter's syndrome	(IV) Mental retardation and reduced hair and skin pigmentation

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Which of the following statements are incorrect?
(A) In bacteria, Bt toxin exists as inactive protoxin
(B) Due to alkaline pH in the gut, the toxin is converted into its active form
(C) The toxin is already present in active form in bacteria
(D) The inactive toxin binds to the surface of midgut and causes cell swelling and lysis.
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Identify the features developed by flowering plants to discourage self-pollination:
(A) Self incompatibility
(B) Synchronized pollen release and stigma receptivity
(C) Different positions of anther and stigma in a flower
(D) Producing bisexual flowers
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Read the passage carefully and answer the Questions
Carbonyl compounds such as aldehydes, ketones, and carboxylic acids play an important role in the biochemical process of plants and animal kingdom.
Many aldehydes and ketones find applications in dye, perfumery and other industries.
The carbonyl carbon atom is \(s p^2\)-hybridized forming three sigma and one pi-bond with oxygen.
C-O bonds are polar bond due to high electronegativity of oxygen than carbon.
Hence the carbonyl carbon behaves as an electrophilic center and oxygen as a nucleophilic centre.
Primary and secondary alcohols yield aldehydes and ketones respectively upon oxidation with variety of oxidizing agents.
The boiling points of aldehydes and ketones differ from hydrocarbons and ethers.
Aldehydes and ketones undergo nucleophilic addition reaction due to presence of electrophilic carbonyl carbon.
Nucleophile and a proton add across the carbon oxygen double bond.
Formalin which is used to preserve biological specimen is an aqueous solution of

The conductivity of 0.001 mol \(\text{L}^{-1}\) acetic acid is \(5.01 \times 10^{-5} \text{ S cm}^{-1}\).
Calculate its dissociation constant if \(\Lambda_m^{\circ}\) for acetic acid is
390.5 \(\text{S cm}^2 \text{mol}^{-1}\).

Choose the correct relation between drift velocity (\( v_d \)) and current density (\( J \)) from the following:

Match List - I with List - II.

List - I	List - II
(A) Cyclosporin A	(I) Lowers blood cholesterol
(B) Streptokinase	(II) Citric acid
(C) Aspergillus niger	(III) Immunosuppressant
(D) Statin	(IV) Clot buster

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Match List-I with List-II

List-I	List-II
(A) The vectors \(\lambda \hat{i}+\hat{j}+2 \hat{k}\) and \(\hat{i}+\lambda \hat{j}+\hat{k}\) are perpendicular if \(\lambda\) is equal to	(I) 1
(B) The vectors \(3 \hat{i}+6 \hat{j}-\hat{k}\) and \(2 \hat{i}+\lambda \hat{j}-2 \hat{k}\) are collinear if \(\lambda\) is equal to	(II) -1
(C) The number of vectors of unit-length which are perpendicular to both the vectors \(\vec{a}=\hat{i}+\hat{j}+2 \hat{k}\) and \(\vec{b}=3 \hat{i}-\hat{j}+5 \hat{k}\) is	(III) \(2 / 3\)
(D) If \(|\vec{a}|=1\) and \(\vec{a}+\vec{b}=\overrightarrow{0}\), then \(|\vec{b}|\) is equal to	(IV) 2

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Single step large mutation leading to speciation is also called: