COMEDK · Physics · 3. Motion In One Dimension
When two objects are moving along a straight line in the same direction, the distance between them increases by \(6 \mathrm{~m}\) in one second. If the objects move with their constant speed towards each other the distance decreases by \(8 \mathrm{~m}\) in one second, then the speed of the objects are :
- A \(14 \mathrm{~ms}^{-1}\) and \(2 \mathrm{~ms}^{-1}\)
- B \(7 \mathrm{~ms}^{-1}\) and \(1 \mathrm{~ms}^{-1}\)
- C \(3.5 \mathrm{~ms}^{-1}\) and \(1 \mathrm{~ms}^{-1}\)
- D \(3.5 \mathrm{~ms}^{-1}\) and \(2 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(7 \mathrm{~ms}^{-1}\) and \(1 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Let the speeds of the two objects be \(v_1\) and \(v_2\) in \(\text{ms}^{-1}\), where \(v_1 > v_2\). When moving in the same direction, the relative speed is \(v_1 - v_2\). The distance between them increases by \(6 \text{ m}\) in \(1 \text{ s}\), so…
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