COMEDK · Physics · 25. Ray Optics
When angle of incidence on one face of the equilateral glass prism is \(3 / 4^{\text {th }}\) of the angle of prism, the ray of light undergoes minimum deviation. If the velocity of light in vacuum is '\(c\)' then the velocity of light in the glass is :
- A \(\dfrac{c}{\sqrt{2}}\)
- B \(\dfrac{c^2}{\sqrt{2}}\)
- C $\dfrac{3 c}{4}$$
- D \(\sqrt{2} c\)
Answer & Solution
Correct Answer
(A) \(\dfrac{c}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
For an equilateral prism, the angle of prism \(A = 60^{\circ}\). The condition for minimum deviation is given by \(i = e\) and \(r_1 = r_2 = r = A/2\). Given that the angle of incidence \(i = \dfrac{3}{4} A\), we have \(i = \dfrac{3}{4} \times 60^{\circ} = 45^{\circ}\). Since…
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