COMEDK · Physics · 23. Alternating Current
When an alternating voltage source \(V=100 \sin \left(100 \pi t+\frac{\pi}{6}\right)\) is applied to a pure capacitor of \(1 \mu \mathrm{~F}\), then the instantaneous value of current through capacitor is
- A \(0.01 \pi \sin \left(100 \pi t+\frac{\pi}{3}\right)\)
- B \(0.01 \pi \sin \left(100 \pi t+\frac{\pi}{6}\right)\)
- C \(0.04 \pi \sin \left(100 \pi t+\frac{\pi}{3}\right)\)
- D \(0.04 \pi \sin \left(100 \pi t+\frac{\pi}{6}\right)\)
Answer & Solution
Correct Answer
(A) \(0.01 \pi \sin \left(100 \pi t+\frac{\pi}{3}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } V=100 \sin \left(100 \pi t+\frac{\pi}{6}\right) \\ & \therefore \phi_1=\frac{\pi}{6} \end{aligned}\) Since, alternating current leads \(\frac{\pi}{2}\) angle from alternating voltage in purely capacitive circuit, hence phase angle of alternating…
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