ExamBro
ExamBro
COMEDK · Physics · 27. Dual Nature of Matter

When a piece of metal is illuminated by a monochromatic light of wavelength \(\lambda\), then stopping potential is \(3 \mathrm{~V}-\mathrm{s}\). When same surface is illuminated by light of wavelength \(2 \lambda\), then stopping potential becomes \(V_{s}\). The value of threshold wavelength for photoelectric emission will be

  1. A \(4 \lambda\)
  2. B \(8 \lambda\)
  3. C \(4 / 3 \lambda\)
  4. D \(6 \lambda\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4 \lambda\)

Step-by-step Solution

Detailed explanation

According to first situation wavelength of incident radiation, \[ \lambda_{1}=\lambda \] Stopping potential, \(V_{01}=3 V_{\mathrm{s}}\) According to Einstein's photoelectric equation,…