COMEDK · Physics · 27. Dual Nature of Matter
When a piece of metal is illuminated by a monochromatic light of wavelength \(\lambda\), then stopping potential is \(3 \mathrm{~V}-\mathrm{s}\). When same surface is illuminated by light of wavelength \(2 \lambda\), then stopping potential becomes \(V_{s}\). The value of threshold wavelength for photoelectric emission will be
- A \(4 \lambda\)
- B \(8 \lambda\)
- C \(4 / 3 \lambda\)
- D \(6 \lambda\)
Answer & Solution
Correct Answer
(A) \(4 \lambda\)
Step-by-step Solution
Detailed explanation
According to first situation wavelength of incident radiation, \[ \lambda_{1}=\lambda \] Stopping potential, \(V_{01}=3 V_{\mathrm{s}}\) According to Einstein's photoelectric equation,…
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