COMEDK · Physics · 23. Alternating Current
When a current of 2.5 A passes through the primary coil of a transformer of 200 number turns, the magnetic flux linked with the secondary coil having 400 turns is \(600 \times 10^{-6}\ T\ m^2\). Find the induced emf in the secondary coil, when the current in the primary coil increases at a rate of \(0.2\ As^{-1}\)
- A \(1.92 \times 10^{-4}\ V\)
- B \(0.92 \times 10^{-4}\ V\)
- C \(0.92 \times 10^{-2}\ V\)
- D \(1.92 \times 10^{-2}\ V\)
Answer & Solution
Correct Answer
(D) \(1.92 \times 10^{-2}\ V\)
Step-by-step Solution
Detailed explanation
The total magnetic flux linked with the secondary coil is proportional to the current in the primary coil, given by the relation: \(N_s \Phi_s = M I_p\) where \(M\) is the mutual inductance. Substituting the given values:…
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