COMEDK · Physics · 28. Atomic Physics
What is the frequency ' \(v\) ' of the electron in Bohr's first orbit of radius ' \(r\) ' of the hydrogen atom?
- A \(v=\dfrac{e^2}{2 \pi \varepsilon_0 h r}\)
- B \(v=\dfrac{e^2}{4 \pi \varepsilon_0 h r}\)
- C \(v=\dfrac{e^2}{2 \pi \varepsilon_0 h r^2}\)
- D \(v=\dfrac{e^2}{4 \pi \varepsilon_0 h r^2}\)
Answer & Solution
Correct Answer
(B) \(v=\dfrac{e^2}{4 \pi \varepsilon_0 h r}\)
Step-by-step Solution
Detailed explanation
For \(n=1\), Bohr's quantization gives: \(mv_{orb}r = \dfrac{h}{2\pi}\) ... (1) Electrostatic force provides centripetal force: \(\dfrac{mv_{orb}^2}{r} = \dfrac{e^2}{4\pi\epsilon_0 r^2}\) ... (2) Dividing (2) by (1):…
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