COMEDK · Physics · 28. Atomic Physics
What is the frequency of the electron in the first orbit of hydrogen atom of orbital radius \(0.5 \times 10^{-10}\)m, if its orbital velocity in that orbit is \(2.2 \times 10^6\ ms^{-1}\).
- A \(3.49 \times 10^{13}\) Hz
- B \(7.0 \times 10^{13}\) Hz
- C \(7.0 \times 10^{15}\) Hz
- D \(3.49 \times 10^{15}\) Hz
Answer & Solution
Correct Answer
(C) \(7.0 \times 10^{15}\) Hz
Step-by-step Solution
Detailed explanation
The frequency \(\nu\) of the electron in its circular orbit is given by the formula: \(\nu = \dfrac{v}{2\pi r}\) Substituting the given values \(v = 2.2 \times 10^6 \text{ ms}^{-1}\) and \(r = 0.5 \times 10^{-10} \text{ m}\):…
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