COMEDK · Physics · 11. Mechanical Properties of Fluids
Water from a tap of cross-sectional area \(1 \mathrm{~cm}^2\), falls vertically downwards at \(2 \mathrm{~m} / \mathrm{s}\). The cross sectional area of the stream, \(20 \mathrm{~cm}\) below the tap is (assume that pressure is constant throughout and the flow is streamlined; \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
- A 1 cm\(^2\)
- B 7.07 cm\(^2\)
- C 2 cm\(^2\)
- D 0.707 cm\(^2\)
Answer & Solution
Correct Answer
(D) 0.707 cm\(^2\)
Step-by-step Solution
Detailed explanation
Let \(A_1 = 1 \text{ cm}^2\) be the cross-sectional area at the tap and \(v_1 = 2 \text{ m/s}\) be the velocity at the tap. Let \(A_2\) be the cross-sectional area at a depth \(h = 20 \text{ cm} = 0.2 \text{ m}\) below the tap, and \(v_2\) be the velocity at that point. Using…
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