COMEDK · Physics · 11. Mechanical Properties of Fluids
Water flows from a tap with steady flow, through a cross sectional area of \(10^{-3} \mathrm{~m}^2\) with a speed of \(0.5 \mathrm{~ms}^{-1}\). Assume the pressure is constant throughout the stream of water. The cross sectional area of the stream \(0.19 \mathrm{~m}\) below the tap is
- A \(2.5 \times 10^{-4} \mathrm{~m}^2\)
- B \(1 \times 10^{-4} \mathrm{~m}^2\)
- C \(5 \times 10^{-5} \mathrm{~m}^2\)
- D \(1 \times 10^{-3} \mathrm{~m}^2\)
Answer & Solution
Correct Answer
(A) \(2.5 \times 10^{-4} \mathrm{~m}^2\)
Step-by-step Solution
Detailed explanation
Let \(A_1 = 10^{-3} \mathrm{~m}^2\) be the cross-sectional area at the tap and \(v_1 = 0.5 \mathrm{~ms}^{-1}\) be the speed of water at the tap. Let \(A_2\) and \(v_2\) be the cross-sectional area and speed at a depth \(h = 0.19 \mathrm{~m}\) below the tap. Using the equation of…
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