COMEDK · Physics · 11. Mechanical Properties of Fluids
Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is \(V\). If the length of the capillary is doubled and the diameter of the bore is halved, then the rate of flow would become
- A \(V / 4\)
- B \(V / 8\)
- C \(16 \mathrm{~V}\)
- D \(V / 32\)
Answer & Solution
Correct Answer
(D) \(V / 32\)
Step-by-step Solution
Detailed explanation
Given, \(V_{1}=V, l_{1}=l, r_{1}=r\) \[ \begin{aligned} &l_{2}=2 l_{1}=2 l \\ &r_{2}=\frac{r_{1}}{2}=\frac{r}{2} \\ &V_{2}=? \end{aligned} \] According to Poiseuille's formula, the rate of flow of liquid through a narrow tube is given as…
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