COMEDK · Physics · 10. Mechanical Properties of Solids
Two wire of same material having radius in ratio 2 : 1 and lengths in ratio 1: 2. If same force is applied on them, then ratio of their change in length will be
- A \(1: 8\)
- B \(1: 2\)
- C \(1: 4\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(A) \(1: 8\)
Step-by-step Solution
Detailed explanation
The change in length \(\Delta L\) of a wire is given by the formula \(\Delta L = \dfrac{FL}{AY}\), where \(F\) is the applied force, \(L\) is the original length, \(A\) is the cross-sectional area, and \(Y\) is Young's modulus of the material. Since both wires are made of the…
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