COMEDK · Physics · 21. Magnetic Effects of Current
Two very long, straight, parallel wires carry steady currents I and 2I respectively. The distance between the wires is d. At a certain instant of time, a point charge q is at a point equidistant from the two wires, in the plane of the wires. Its instantaneous velocity is v perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is
- A \(\dfrac{\mu_o I q v}{\pi d}\)
- B \(\dfrac{2 \mu_o I q v}{\pi d}\)
- C \(\dfrac{\mu_o I q v}{2 \pi d}\)
- D zero
Answer & Solution
Correct Answer
(D) zero
Step-by-step Solution
Detailed explanation
The magnetic field due to both wires at any point in the plane of the wires is perpendicular to that plane. The velocity \(v\) of charge \(q\) is also perpendicular to the plane of the wires. Since \(\vec{v}\) and \(\vec{B}\) are both perpendicular to the same plane, they are…
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