COMEDK · Physics · 21. Magnetic Effects of Current
Two very long straight parallel wires carry currents \(i\) and \(2 i\) in opposite directions. The distance between the wires is \(r\). At a certain instant of time a point charge \(q\) is at a point equidistant from the two wires in the plane of the wires. Its instantaneous velocity \(v\) is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is
- A zero
- B \(\frac{3 \mu_0}{2 \pi} \frac{i q v}{r}\)
- C \(\frac{\mu_0}{\pi} \frac{i q v}{r}\)
- D \(\frac{\mu_0}{2 \pi} \frac{i q v}{r}\)
Answer & Solution
Correct Answer
(A) zero
Step-by-step Solution
Detailed explanation
The magnetic field induction at \(P\) due to currents through both the wires is \(B=\frac{\mu_0}{4 \pi} \frac{2 i}{(r / 2)}+\frac{\mu_0}{4 \pi} \frac{2(2 i)}{(r / 2)}=\frac{\mu_0}{4 \pi} \cdot \frac{12 i}{r}\) acting perpendicular to plane of wire inwards. Now, \(B\) and \(v\)…
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