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COMEDK · Physics · 17. Electrostatics

Two unlike charges of the same magnitude \(Q\) are placed at a distance \(d\). The intensity of the electric field at the middle point is the line joining the two charges is

  1. A zero
  2. B \(\frac{8 Q}{4 \pi \varepsilon_0 d^2}\)
  3. C \(\frac{6 Q}{4 \pi \varepsilon_0 d^2}\)
  4. D \(\frac{4 Q}{4 \pi \varepsilon_0 d^2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{8 Q}{4 \pi \varepsilon_0 d^2}\)

Step-by-step Solution

Detailed explanation

The magnitude of electric field due to charge at point \(A\) is \(E_A=|\mathbf{E}|=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{\left(\frac{d}{2}\right)^2}=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{4 Q}{d^2}\) Similarly,…
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