COMEDK · Physics · 11. Mechanical Properties of Fluids
Two small drops of mercury, each of radius \(r\), coalesce to form a single large drop of radius \(R\). The ratio of the total surface energies before and after the change is
- A \(1: 2^{1 / 3}\)
- B \(2^{1 / 3}: 1\)
- C \(2: 1\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(B) \(2^{1 / 3}: 1\)
Step-by-step Solution
Detailed explanation
As, radius of bigger drop, \(R=n^{1 / 3} r=2^{1 / 3} r\)…
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