COMEDK · Physics · 15. Oscillations
Two simple harmonic motions are represented by equations \(y_1=0.5 \sin \left[200 \pi t+\dfrac{\pi}{3}\right]\) and \(y_1=0.5 \cos \pi t\). The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is:
- A \(\dfrac{\pi}{2}\)
- B \(\dfrac{-\pi}{6}\)
- C \(\dfrac{\pi}{6}\)
- D \(\dfrac{-\pi}{2}\)
Answer & Solution
Correct Answer
(B) \(\dfrac{-\pi}{6}\)
Step-by-step Solution
Detailed explanation
The first equation is \(y_1 = 0.5 \sin \left(200 \pi t + \dfrac{\pi}{3}\right)\). The velocity \(v_1\) is given by the derivative…
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