COMEDK · Physics · 17. Electrostatics
Two protons are kept at a separation of \(40 Å F_{n}\) is the nuclear force and \(F_{\varepsilon}\) is the electrostatic force between them. Then,
- A \(F_{n}< < F_{e}\)
- B \(F_{n} \approx F_{e}\)
- C \(F_{n} \gg>F_{e}\)
- D \(F_{n}=F_{e}\)
Answer & Solution
Correct Answer
(C) \(F_{n} \gg>F_{e}\)
Step-by-step Solution
Detailed explanation
Nuclear force \(F_{n}\) are attractive in nature. As in the given case, the two protons are kept at a separation of \(40 Å\) (short range), hence in this range, nuclear force \(F_{n}\) is much greater than the electrostatic force \(F_{e}\). i.e. \(F_{n} \gg F_{e}\)
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