COMEDK · Physics · 17. Electrostatics
Two-point charges of equal magnitude 0.01 C and opposite in sign are separated by 0.2mm, forming an electric dipole. The electric dipole moment of the dipole is:
- A \(2 \times 10^{-6}\ Cm\) along the line joining the two charges and the direction of the dipole moment vector is from negative to positive 0.01 C
- B \(4 \times 10^{-6}\ Cm\) along the line joining the two charges and the direction of the dipole moment vector is from positive to negative 0.01 C
- C \(2 \times 10^{6}\ Cm\) along the line joining the two charges and the direction of the dipole moment vector is from positive to negative 0.01 C
- D \(2 \times 10^{-3}\ Cm\) along the line joining the two charges and the direction of the dipole moment vector is from negative to positive 0.01 C
Answer & Solution
Correct Answer
(A) \(2 \times 10^{-6}\ Cm\) along the line joining the two charges and the direction of the dipole moment vector is from negative to positive 0.01 C
Step-by-step Solution
Detailed explanation
Magnitude of charge, \(q = 0.01\text{ C} = 10^{-2}\text{ C}\) Separation between charges, \(d = 0.2\text{ mm} = 0.2 \times 10^{-3}\text{ m} = 2 \times 10^{-4}\text{ m}\) Electric dipole moment, \(p = q \times d\)…
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