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COMEDK · Physics · 17. Electrostatics

Two point charges \(20 \mu \mathrm{C}\) and \(-10 \mu \mathrm{C}\) are separated by a distance of \(1 \mathrm{~m}\) in air. At what point on the line joining the two charges, the electric potential is zero.

  1. A \(0.67 \mathrm{~m}\) from the charge \(20 \mu \mathrm{C}\)
  2. B \(0.5 \mathrm{~m}\) from the charge \(10 \mu \mathrm{C}\)
  3. C \(0.76 \mathrm{~m}\) from the charge \(20 \mu \mathrm{C}\)
  4. D \(0.25 \mathrm{~m}\) from the charge \(10 \mu \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.67 \mathrm{~m}\) from the charge \(20 \mu \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Let the two charges be \(q_1 = 20 \times 10^{-6} \text{ C}\) and \(q_2 = -10 \times 10^{-6} \text{ C}\), separated by a distance \(d = 1 \text{ m}\). Let the point where the electric potential is zero be at a distance \(x\) from \(q_1\) along the line joining the charges. The…
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