COMEDK · Physics · 17. Electrostatics
Two identical conducting balls having unequal positive charges \(q_1\) and \(q_2\) are separated by a distance \(r\). If they are made to touch each other and then separated to the same distance, the force between them will be
- A zero
- B More than before
- C Same as before
- D Less than before
Answer & Solution
Correct Answer
(B) More than before
Step-by-step Solution
Detailed explanation
Initial force: \(F_1 = k\dfrac{q_1 q_2}{r^2}\) After touching, each ball gets charge \(q' = \dfrac{q_1+q_2}{2}\) New force: \(F_2 = k\dfrac{\left(\dfrac{q_1+q_2}{2}\right)^2}{r^2}\) Comparing: since \(q_1 \neq q_2\), \((q_1-q_2)^2 > 0\)…
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