COMEDK · Physics · 19. Current Electricity

Two electric bulbs \(A\) and \(B\) are rated as \(60 \mathrm{~W}\) and \(100 \mathrm{~W}\). They are connected in parallel to the same source. Then,

A Both draw the same current
B \(A\) draws more current than \(B\)
C \(B\) draws more current than \(A\)
D currents drawn are in the ratio of their resistances

Verified Solution

Answer & Solution

Correct Answer

(C) \(B\) draws more current than \(A\)

Step-by-step Solution

Detailed explanation

Given, power of bulb \(A, P_{A}=60 \mathrm{~W}\) Power of bulb \(B, P_{B}=100 \mathrm{~W}\) Since, both bulbs are connected to the same power source in parallel combination. Thus, \(P_{A}=\frac{V^{2}}{R_{A}}=60 \mathrm{~W}\) and \(P_{B}=\frac{V^{2}}{R_{B}}=100 \mathrm{~W}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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