COMEDK · Physics · 29. Nuclear Physics
Two deuterons are fused to form one alpha particle. If binding energy per nucleon of deuterium is 1.05 MeV and that of alpha particle is 7 MeV, what is the energy released in the formation of one alpha particle from the fusing of two deuterons?
- A \(26.8\ \text{MeV}\)
- B \(28.3\ \text{MeV}\)
- C \(23.8\ \text{MeV}\)
- D \(24.8\ \text{MeV}\)
Answer & Solution
Correct Answer
(C) \(23.8\ \text{MeV}\)
Step-by-step Solution
Detailed explanation
The fusion reaction is given by: \(2\ ^{2}_{1}\text{H} \rightarrow\ ^{4}_{2}\text{He}\) Total binding energy of two deuterons = \(2 \times (2 \times 1.05) = 4.2\ \text{MeV}\) Total binding energy of one alpha particle = \(4 \times 7 = 28\ \text{MeV}\) Energy released = Total…
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