COMEDK · Physics · 17. Electrostatics
Two charges '\(-q\)' each are fixed, separated by distance '\(2 d\)'. A third charge '\(q\)' of mass '\(m\)' placed at the mid-point is displaced slightly by '\(x\)' \((x< < d)\) perpendicular to the line joining the two fixed charges as shown in Fig. The time period of oscillation of '\(q\)' will be

- A \(\mathrm{T}=\sqrt{\dfrac{4 \varepsilon_0 \mathrm{~m} \pi^3 \mathrm{~d}^3}{\mathrm{q}^2}}\)
- B \(\mathrm{T}=\sqrt{\dfrac{8 \varepsilon_0 \mathrm{~m} \pi^3 \mathrm{~d}^3}{\mathrm{q}^3}}\)
- C \(\mathrm{T}=\sqrt{\dfrac{8 \varepsilon_0 \mathrm{~m} \pi^3 \mathrm{~d}^3}{\mathrm{q}^2}}\)
- D \(\mathrm{T}=\sqrt{\dfrac{8 \varepsilon_0 \mathrm{~m} \pi^2 \mathrm{~d}^3}{\mathrm{q}^2}}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{T}=\sqrt{\dfrac{8 \varepsilon_0 \mathrm{~m} \pi^3 \mathrm{~d}^3}{\mathrm{q}^2}}\)
Step-by-step Solution
Detailed explanation
Let the two fixed charges \(-q\) be located at \((-d, 0)\) and \((d, 0)\). The charge \(q\) is at \((0, x)\). The distance \(r\) between the charge \(q\) and each of the fixed charges is \(r = \sqrt{d^2 + x^2}\). The force exerted by each fixed charge on \(q\) is…
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