COMEDK · Physics · 17. Electrostatics
Two charges \(q\) and \(-2 q\) are separated by a distance \(d\). If the electric intensity at the site of \(q\) is \(E\), then the electric field at the site of \(-2 q\) is
- A \(E\)
- B \(E\) / 2
- C \(-2 E\)
- D \(-E / 2\)
Answer & Solution
Correct Answer
(B) \(E\) / 2
Step-by-step Solution
Detailed explanation
Electric field intensity at a point due to a charge \(q\) is given by \[ E=\frac{F}{q} \] As, the force between the charges is mutual, so the electric field intensity due to charge \(-2 q\) is \[ E^{\prime}=\frac{F}{|-2 q|}=\frac{1}{2} \frac{F}{q}=\frac{E}{2} \]
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