COMEDK · Physics · 4. Motion In Two Dimensions
Two balls are thrown horizontally, one from the window of first floor which is \(3 \mathrm{~m}\) high from the ground and second from the second floor which is \(6 \mathrm{~m}\) high from the ground, of a multi storey building, with the same speed of \(6 \mathrm{~ms}^{-1}\). Calculate the distance that will separate the two balls when they hit the ground.
- A 1.81 m
- B 0.39 m
- C 1.94 m
- D 2.28 m
Answer & Solution
Correct Answer
(C) 1.94 m
Step-by-step Solution
Detailed explanation
The time taken for a ball thrown horizontally from a height \(h\) to reach the ground is given by \(t = \sqrt{\dfrac{2h}{g}}\). For the first ball thrown from height \(h_1 = 3\) m: \(t_1 = \sqrt{\dfrac{2 \times 3}{9.8}} = \sqrt{\dfrac{6}{9.8}} \approx 0.7825\) s. The horizontal…
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