COMEDK · Physics · 27. Dual Nature of Matter
Threshold wavelength for photoelectric emission from a metal surface is \(5200 Å\). Photoelectrons will be emitted when this surface is illuminated with monochromatic radiation from
- A \(50 \mathrm{~W}\) IR-lamp
- B \(10 \mathrm{~W}\) IR-lamp
- C \(1 \mathrm{~W}\) IR-lamp
- D \(50 \mathrm{~W} \mathrm{UV}-\operatorname{lamp}\)
Answer & Solution
Correct Answer
(D) \(50 \mathrm{~W} \mathrm{UV}-\operatorname{lamp}\)
Step-by-step Solution
Detailed explanation
Threshold wavelength of the metal, \(\lambda_{0}=5200 Å\) \[ =5200 \times 10^{-10} \mathrm{~m} \] Frequency of the radiation, \(v_{0}=\frac{c}{\lambda}\)…
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