COMEDK · Physics · 17. Electrostatics
Three charges, \(\mathrm{Q},-\mathrm{q}\) and 2 q are placed at the vertices of a right-angled isosceles triangle. What is the value of \(q\) for the net electrostatic energy of the configuration to be zero?

- A \(Q\left[\dfrac{1}{2 \sqrt{2}}-1\right]\)
- B \(Q\left[1+\dfrac{1}{2 \sqrt{2}}\right]\)
- C \(Q\left[1-\dfrac{1}{2 \sqrt{2}}\right]\)
- D \(Q\left[\dfrac{2 \sqrt{2}+1}{2}\right]\)
Answer & Solution
Correct Answer
(C) \(Q\left[1-\dfrac{1}{2 \sqrt{2}}\right]\)
Step-by-step Solution
Detailed explanation
The electrostatic potential energy \(U\) of a system of point charges is given by the sum of the potential energies of all pairs of charges: \(U = \sum \dfrac{k q_i q_j}{r_{ij}}\). The charges are \(Q\), \(2q\), and \(-q\). The distances between the pairs are \(r\), \(r\), and…
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