COMEDK · Physics · 19. Current Electricity
Three bulbs of \(40 \mathrm{~W}, 60 \mathrm{~W}\), and \(100 \mathrm{~W}\) are arranged in series with a \(220 \mathrm{~V}\) source. The maximum light is obtained from
- A 100 W
- B 60 W
- C 40 W
- D All give the same light
Answer & Solution
Correct Answer
(C) 40 W
Step-by-step Solution
Detailed explanation
The power consumed by a bulb is given by \(P = I^2 R\), where \(I\) is the current flowing through the bulb and \(R\) is its resistance. Since the bulbs are connected in series, the same current \(I\) flows through all of them. The resistance \(R\) of a bulb is related to its…
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