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COMEDK · Physics · 26. Wave Optics

The width of the fringes obtained in the Young's double slit experiment is \(2.6 \mathrm{~mm}\) when light of wave length \(6000^{\circ} \mathrm{A}\) is used. If the whole apparatus is immersed in a liquid of refractive index 1.3 the new fringe width will be :

  1. A 2.6 mm
  2. B 2 mm
  3. C 5.2 mm
  4. D 4 mm
Verified Solution

Answer & Solution

Correct Answer

(B) 2 mm

Step-by-step Solution

Detailed explanation

The fringe width \(\beta\) in Young's double slit experiment is given by the formula \(\beta = \dfrac{\lambda D}{d}\), where \(\lambda\) is the wavelength of light, \(D\) is the distance between the slits and the screen, and \(d\) is the distance between the slits. When the…