COMEDK · Physics · 28. Atomic Physics
The wavelength of the first line of Lyman series for \(\mathrm{H}\) - atom is equal to that of the second line of Balmer series for a \(\mathrm{H}\)-like ion. The atomic number \(\mathrm{Z}\) of \(\mathrm{H}\)-like ion is
- A 3
- B 4
- C 1
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
The wavelength \(\lambda\) for a transition in a hydrogen-like ion is given by the Rydberg formula: \(\dfrac{1}{\lambda} = R Z^2 \left( \dfrac{1}{n_1^2} - \dfrac{1}{n_2^2} \right)\). For the first line of the Lyman series in H-atom (\(Z=1\)): \(n_1 = 1\), \(n_2 = 2\).…
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