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COMEDK · Physics · 2. Units and Dimensions

The velocity of a body moving in a viscous medium is given by \(v = \dfrac{A}{B+C}\left[1 - e^{\frac{-t}{B}}\right]\) where t is time; dimensions of A and C are

  1. A \([M^1L^1T^0],\ [M^0L^0T^{-1}]\)
  2. B \([M^1L^1T^1],\ [M^0L^0T^1]\)
  3. C \([M^0L^1T^1],\ [M^0L^0T^1]\)
  4. D \([M^0L^1T^0],\ [M^0L^0T^1]\)
Verified Solution

Answer & Solution

Correct Answer

(D) \([M^0L^1T^0],\ [M^0L^0T^1]\)

Step-by-step Solution

Detailed explanation

The exponent of an exponential function must be dimensionless. Therefore, the dimension of \(\dfrac{t}{B}\) is \([M^0L^0T^0]\). \([B] = [t] = [M^0L^0T^1]\) By the principle of homogeneity, quantities added or subtracted must have the same dimensions. Since \(B\) and \(C\) are…
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