COMEDK · Physics · 27. Dual Nature of Matter
The variation of the stopping potential (\(V_0\)) with the frequency of incident radiation(n) is as given below.
[\(n_0\) - threshold frequency. h- Planck's constant e- electronic charge] then the slope of the graph AB with the frequency axis is:
- A \(\dfrac{h}{e}\)
- B \(\dfrac{n_0}{V_0}\)
- C \(\dfrac{hn_0}{V_0}\)
- D \(\dfrac{V_0}{n_0}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{h}{e}\)
Step-by-step Solution
Detailed explanation
According to Einstein's photoelectric equation, the maximum kinetic energy of emitted photoelectrons is given by: \(K_{\text{max}} = hn - \Phi\) where \(h\) is Planck's constant, \(n\) is the frequency of incident radiation, and \(\Phi\) is the work function of the metal. We…
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