COMEDK · Physics · 14. Kinetic Theory of Gases
The total number of degrees of freedom associated with \(2 \mathrm{~cm}^3\) of Nitrogen gas at normal temperature and pressure is:
[Given Avogadro number as ' N ' ]
- A \(\dfrac{N}{4480}\)
- B \(\dfrac{N}{44800}\)
- C \(\dfrac{N}{22400}\)
- D \(\dfrac{N}{2240}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{N}{2240}\)
Step-by-step Solution
Detailed explanation
At normal temperature and pressure (NTP), the molar volume of an ideal gas is \(22400 \text{ cm}^3\). The number of moles \(n\) in \(2 \text{ cm}^3\) of Nitrogen gas is given by \(n = \dfrac{V}{V_{m}} = \dfrac{2}{22400} = \dfrac{1}{11200}\) moles. Nitrogen (\(N_2\)) is a…
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