COMEDK · Physics · 19. Current Electricity
The terminals of a \(18 \mathrm{~V}\) battery with an internal resistance of \(1.5 \Omega\) are connected to a circular wire of resistance \(24 \Omega\) at two points distant at one quarter of the circumference of a circular wire. The current through the bigger arc of the circle will be
- A \(0.75 \mathrm{~A}\)
- B \(1.5 \mathrm{~A}\)
- C \(2.25 \mathrm{~A}\)
- D \(3 \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(0.75 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Since, the terminals of battery is connected at one quarter distance. Hence, ratio of lengths between two parts will be…
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