COMEDK · Physics · 12. Thermal Properties of Matter
The temperature of two bodies \(A\) and \(B\) are \(727^{\circ} \mathrm{C}\) and \(327^{\circ} \mathrm{C}\) respectively, the ratio \(H_{A}: H_{B}\) of the rates of heat radiated by them is
- A \(727: 327\)
- B \(5: 3\)
- C \(25: 9\)
- D \(625: 81\)
Answer & Solution
Correct Answer
(D) \(625: 81\)
Step-by-step Solution
Detailed explanation
Given, \(T_{A}=727^{\circ} \mathrm{C}\) and \(T_{B}=327^{\circ} \mathrm{C}\) As we know, rate of heat radiated, \(Q \propto T^{4}\) \(\Rightarrow \quad \frac{Q_{\mathrm{A}}}{Q_{B}}=\frac{H_{A}}{H_{B}}=\left(\frac{273+727}{273+327}\right)^{4}=\frac{625}{81}\)
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