COMEDK · Physics · 16. Waves and Sound
The string of length \(2 \mathrm{~m}\) is fixed at both ends. If the string vibrates in its fourth normal mode with a frequency of \(500 \mathrm{~Hz}\), then the waves would travel on it with a velocity of
- A \(125 \mathrm{~m} / \mathrm{s}\)
- B \(250 \mathrm{~m} / \mathrm{s}\)
- C \(500 \mathrm{~m} / \mathrm{s}\)
- D \(1000 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(500 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
The frequency of the \(n\)-th normal mode of a string of length \(L\) fixed at both ends is given by \(f_n = \dfrac{n v}{2L}\), where \(v\) is the wave velocity. Given \(L = 2 \text{ m}\), \(n = 4\), and \(f_4 = 500 \text{ Hz}\). Substituting the values into the formula:…
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