COMEDK · Physics · 27. Dual Nature of Matter
The stopping potential when a metal surface is illuminated by light of wavelength \(\lambda\) is 15 V . The stopping potential when the same surface is illuminated by light of wavelength \(4 \lambda\) is 3 V . The ratio of threshold wavelength to the initial incident wavelength \(\lambda\) is:
- A \(15: 1\)
- B \(1: 16\)
- C \(1: 15\)
- D \(16: 1\)
Answer & Solution
Correct Answer
(D) \(16: 1\)
Step-by-step Solution
Detailed explanation
From Einstein's photoelectric equation, the stopping potential \(V_s\) is given by \(eV_s = \dfrac{hc}{\lambda} - \Phi\), where \(\Phi\) is the work function of the metal and \(\lambda_0\) is the threshold wavelength such that \(\Phi = \dfrac{hc}{\lambda_0}\). For the first…
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