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COMEDK · Physics · 11. Mechanical Properties of Fluids

The speeds of air-flow on the upper and lower surfaces of a wing of an aeroplane are \(v_1\) and \(v_2\), respectively. If \(A\) is the cross-sectional area of the wing and \(\rho\) is the density of air, then the upward lift is

  1. A \(\dfrac{1}{2} \rho A\left(v_1+v_2\right)\)
  2. B \(\dfrac{1}{2} \rho A\left(v_1-v_2\right)\)
  3. C \(\dfrac{1}{2} \rho A\left(v_1^2-v_2^2\right)\)
  4. D \(\dfrac{1}{2} \rho A\left(v_1^2+v_2^2\right)\)
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Answer & Solution

Correct Answer

(C) \(\dfrac{1}{2} \rho A\left(v_1^2-v_2^2\right)\)

Step-by-step Solution

Detailed explanation

According to Bernoulli's principle for streamline flow, the pressure \(P\) and velocity \(v\) at any two points on a streamline are related by \(P + \dfrac{1}{2} \rho v^2 = \text{constant}\). Let \(P_1\) and \(P_2\) be the pressures on the upper and lower surfaces of the wing…
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