COMEDK · Physics · 11. Mechanical Properties of Fluids
The speeds of air-flow on the upper and lower surfaces of a wing of an aeroplane are \(v_1\) and \(v_2\), respectively. If \(A\) is the cross-sectional area of the wing and \(\rho\) is the density of air, then the upward lift is
- A \(\dfrac{1}{2} \rho A\left(v_1+v_2\right)\)
- B \(\dfrac{1}{2} \rho A\left(v_1-v_2\right)\)
- C \(\dfrac{1}{2} \rho A\left(v_1^2-v_2^2\right)\)
- D \(\dfrac{1}{2} \rho A\left(v_1^2+v_2^2\right)\)
Answer & Solution
Correct Answer
(C) \(\dfrac{1}{2} \rho A\left(v_1^2-v_2^2\right)\)
Step-by-step Solution
Detailed explanation
According to Bernoulli's principle for streamline flow, the pressure \(P\) and velocity \(v\) at any two points on a streamline are related by \(P + \dfrac{1}{2} \rho v^2 = \text{constant}\). Let \(P_1\) and \(P_2\) be the pressures on the upper and lower surfaces of the wing…
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