COMEDK · Physics · 1. Mathematics in Physics
The sides of a parallelogram are represented by vectors \(\vec{p}=5 \hat{\mathrm{i}}-4 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}\) and \(\vec{q}=3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-\hat{\mathrm{k}}\). Then, the area of the parallelogram is
- A \(\sqrt{72}\) sq units
- B 72 sq units
- C \(\sqrt{684}\) sq units
- D 171 sq units
Answer & Solution
Correct Answer
(C) \(\sqrt{684}\) sq units
Step-by-step Solution
Detailed explanation
The area of a parallelogram with adjacent sides represented by vectors \(\vec{p}\) and \(\vec{q}\) is given by the magnitude of their cross product, \(|\vec{p} \times \vec{q}|\). First, calculate the cross product \(\vec{p} \times \vec{q}\):…
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