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COMEDK · Physics · 28. Atomic Physics

The shortest wavelengths of Paschen, Lymen and Balmer series are in the ratio

  1. A \(2:1:3\)
  2. B \(3: 1: 2\)
  3. C \(4: 1: 9\)
  4. D \(9: 1: 4\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(9: 1: 4\)

Step-by-step Solution

Detailed explanation

The wavelength \(\lambda\) for a transition in a hydrogen-like atom is given by the Rydberg formula: \(\dfrac{1}{\lambda} = R Z^2 \left( \dfrac{1}{n_1^2} - \dfrac{1}{n_2^2} \right)\). For the shortest wavelength of any series, the transition occurs from \(n_2 = \infty\) to…