COMEDK · Physics · 5. Laws of Motion
The resultant of two forces acting at an angle of \(120^{\circ}\) is \(10 \mathrm{~kg}-\mathrm{W}\) and is perpendicular to one of the forces. That force is
- A \(\dfrac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{W}\)
- B \(10 \mathrm{~kg}-\mathrm{W}\)
- C \(20 \sqrt{3} \mathrm{~kg}-\mathrm{W}\)
- D \(10 \sqrt{3} \mathrm{~kg}-\mathrm{W}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{W}\)
Step-by-step Solution
Detailed explanation
Let the two forces be \(F_1\) and \(F_2\). The angle between them is \(\theta = 120^{\circ}\). The resultant \(R = 10 \text{ kg-W}\) is perpendicular to \(F_1\). The formula for the angle \(\alpha\) that the resultant makes with \(F_1\) is given by…
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