COMEDK · Physics · 19. Current Electricity
The resistance of a heating element is found to be \(120 \Omega\) at room temperature which is \(20^{\circ} \mathrm{C}\). If the temperature coefficient of the material of the resistor is \(1.6 \times 10^{-4} C^{-1}\) and the resistance is found to be \(160 \Omega\), the temperature of the element is:
- A \(1203^{\circ} \mathrm{C}\)
- B \(2103^{\circ} \mathrm{C}\)
- C \(2310^{\circ} \mathrm{C}\)
- D \(2013^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(2103^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
The resistance of a conductor at a temperature \(T\) is given by the formula \(R_T = R_0 [1 + \alpha(T - T_0)]\), where \(R_0\) is the resistance at room temperature \(T_0\), \(R_T\) is the resistance at temperature \(T\), and \(\alpha\) is the temperature coefficient of…
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