COMEDK · Physics · 28. Atomic Physics
The ratio of the speed of electron in the \(4^{\text {th }}\) orbit of \(\mathrm{Li}^{++}\)to the speed of electron in the ground state of hydrogen atom will be:
- A \(\dfrac{3}{4}\)
- B \(\dfrac{16}{9}\)
- C \(\dfrac{4}{3}\)
- D \(\dfrac{9}{16}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{3}{4}\)
Step-by-step Solution
Detailed explanation
The speed of an electron in the \(n^{th}\) orbit of a hydrogen-like atom with atomic number \(Z\) is given by the formula \(v_n = v_0 \dfrac{Z}{n}\), where \(v_0\) is the speed of an electron in the ground state of the hydrogen atom (\(Z=1, n=1\)). For the \(4^{th}\) orbit of…
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