COMEDK · Physics · 12. Thermal Properties of Matter
The rate of heat conduction in the given two metal rods having the same length is found to be the same when the temperature difference between the ends is kept \(30^{\circ} \mathrm{C}\) If the area of cross section of the first rod is \(8 \times 10^{-2} \mathrm{~m}^2\) then what will be area of cross section of the second rod? [ Given that the ratio of the thermal conductivity of the first rod to that of the second rod is \(1: 4\) ]
- A \(4 \times 10^{-2} \mathrm{~m}^2\)
- B \(2 \times 10^{-2} \mathrm{~m}^2\)
- C \(4 \times 10^{-4} \mathrm{~m}^2\)
- D \(2 \times 10^{-4} \mathrm{~m}^2\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-2} \mathrm{~m}^2\)
Step-by-step Solution
Detailed explanation
The rate of heat conduction \(H\) through a rod is given by the formula \(H = \dfrac{KA \Delta T}{L}\), where \(K\) is the thermal conductivity, \(A\) is the area of cross-section, \(\Delta T\) is the temperature difference, and \(L\) is the length of the rod. Given that the…
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