COMEDK · Physics · 16. Waves and Sound
The number of possible natural oscillations of air column in a pipe closed at one end of length \(85 \mathrm{~cm}\) whose frequencies lie below \(1250 \mathrm{~Hz}\) are (velocity of sound \(=340 \mathrm{~ms}^{-1}\))
- A 6
- B 5
- C 4
- D 8
Answer & Solution
Correct Answer
(A) 6
Step-by-step Solution
Detailed explanation
For a pipe closed at one end, the frequencies of natural oscillations are given by the formula \(f_n = \dfrac{(2n-1)v}{4L}\), where \(n = 1, 2, 3, \dots\) is the harmonic number, \(v\) is the velocity of sound, and \(L\) is the length of the pipe. Given \(v = 340 \text{ m/s}\)…
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