COMEDK · Physics · 3. Motion In One Dimension
The nucleus of a helium atom travels along the inside of a straight hollow tube \(4 \mathrm{~m}\) long which forms part of a particle accelerator. If one assumes uniform acceleration, how long is the particle in the tube if it enters at a speed of \(2000 \mathrm{~m} / \mathrm{s}\) and leaves at \(8000 \mathrm{~m} / \mathrm{s}\)
- A \(3.3 \times 10^{-4} \mathrm{~s}\)
- B \(0.6 \times 10^{-4}\) s
- C \(4 \times 10^{-4} \mathrm{~s}\)
- D \(8 \times 10^{-4} \mathrm{~s}\)
Answer & Solution
Correct Answer
(D) \(8 \times 10^{-4} \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Given the length of the tube \(s = 4 \text{ m}\), the initial velocity \(u = 2000 \text{ m/s}\), and the final velocity \(v = 8000 \text{ m/s}\). Assuming uniform acceleration, the average velocity \(v_{avg}\) is given by the formula \(v_{avg} = \dfrac{u + v}{2}\). Substituting…
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