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COMEDK · Physics · 14. Kinetic Theory of Gases

The mean energy per molecule for a diatomic gas is

  1. A \(\frac{5 k_B T}{N}\)
  2. B \(\frac{5 k_B T}{2 N}\)
  3. C \(\frac{5 k_B T}{2}\)
  4. D \(\frac{3 k_B T}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{5 k_B T}{2}\)

Step-by-step Solution

Detailed explanation

For an ideal gas, mean kinetic energy per molecule \(=\frac{f}{2} k_B T\) For diatomic gas, degree of freedom, \(f=5\) \(\therefore\) K.E per molecule \(=\frac{5 k_B T}{2}\)