COMEDK · Physics · 14. Kinetic Theory of Gases
The mean energy per molecule for a diatomic gas is:
- A \(\left(\dfrac{3}{2 N}\right) \mathrm{K}_{\mathrm{B}} \mathrm{T}\)
- B \(\left(\dfrac{3}{2}\right) \mathrm{K}_{\mathrm{B}} \mathrm{T}\)
- C \(\left(\dfrac{5}{2 N}\right) \mathrm{K}_{\mathrm{B}} \mathrm{T}\)
- D \(\left(\dfrac{5}{2}\right) \mathrm{K}_{\mathrm{B}} \mathrm{T}\)
Answer & Solution
Correct Answer
(D) \(\left(\dfrac{5}{2}\right) \mathrm{K}_{\mathrm{B}} \mathrm{T}\)
Step-by-step Solution
Detailed explanation
A diatomic gas molecule at moderate temperatures possesses 5 degrees of freedom: 3 translational and 2 rotational degrees of freedom. According to the law of equipartition of energy, each degree of freedom contributes \(\dfrac{1}{2} K_{B} T\) to the average energy of the…
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